{"id":257635,"date":"2024-04-04T17:19:39","date_gmt":"2024-04-04T17:19:39","guid":{"rendered":"https:\/\/namso-gen.co\/blog\/?p=257635"},"modified":"2024-04-04T17:19:39","modified_gmt":"2024-04-04T17:19:39","slug":"how-to-sort-by-value-in-dictionary-python-2","status":"publish","type":"post","link":"https:\/\/namso-gen.co\/blog\/how-to-sort-by-value-in-dictionary-python-2\/","title":{"rendered":"How to sort by value in dictionary Python?"},"content":{"rendered":"

Sorting a dictionary by value is a common task in Python that can be accomplished using the sorted() function along with lambda functions. In this article, we will explore the different steps involved in sorting a dictionary by its values.<\/p>\n

To sort a dictionary by value in Python, we can follow these steps:<\/p>\n

1. Define a dictionary with key-value pairs.
\n2. Use the sorted() function along with a lambda function to specify the sorting criteria.
\n3. Pass the dictionary items and the lambda function to the sorted() function.
\n4. Assign the sorted dictionary items to a new variable.<\/p>\n

Now, let’s look at an example to illustrate the process:<\/p>\n

“`python
\n# Step 1: Define a dictionary
\nunsorted_dict = {‘apple’: 5, ‘banana’: 3, ‘orange’: 8, ‘grape’: 2}<\/p>\n

# Step 2 and 3: Use sorted() with a lambda function to sort by value
\nsorted_dict = dict(sorted(unsorted_dict.items(), key=lambda x: x[1]))<\/p>\n

# Step 4: Print the sorted dictionary
\nprint(sorted_dict)
\n“`<\/p>\n

Output:
\n“`
\n{‘grape’: 2, ‘banana’: 3, ‘apple’: 5, ‘orange’: 8}
\n“`<\/p>\n

In the above example, we created an unsorted dictionary with key-value pairs representing fruits and their quantities. Then we used the sorted() function to sort the dictionary items based on their values. The lambda function `x[1]` specifies that we want to sort by the second element in each item, which corresponds to the values. Finally, the sorted dictionary is printed, resulting in a sorted dictionary based on the values.<\/p>\n

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