<\/span><\/h2>\n\n**To print a pointer value in C, you can use the printf() function along with the %p format specifier.**<\/p>\n
Here’s an example that demonstrates how to print a pointer value in C:<\/p>\n
“`c
\n#include <\/p>\nint main() {
\n int num = 42;
\n int* ptr = #<\/p>\n
printf(“Pointer value: %pn”, (void*)ptr);<\/p>\n
return 0;
\n}
\n“`<\/p>\n
In this code snippet, we declare an integer variable `num` with a value of 42. Then, we declare an integer pointer `ptr` and assign the memory address of `num` to it using the address-of operator `&`. Finally, using the printf() function, we print the value of the pointer `ptr` using the `%p` format specifier. Note that we cast `ptr` to `(void*)` before passing it to printf() to avoid any potential warnings.<\/p>\n
When executing this code, you will see an output similar to:<\/p>\n
“`
\nPointer value: 0x7ffcfa3f89f4
\n“`<\/p>\n
The hexadecimal value displayed is the memory address of `num`. Please note that the actual memory address may vary each time you run the program.<\/p>\n