Convert the array to an object:<\/li>\n<\/p>\n
const array = [\"key1\", \"value1\", \"key2\", \"value2\"];
\nconst obj = Object.fromEntries(array.map((_, i) => (i % 2 === 0 ? [array[i], array[i + 1]] : [])));
\nconsole.log(obj[\"key1\"]); \/\/ Output: value1<\/code><\/pre>\n<\/p>\n
In this example, we convert the array into an object using the Object.fromEntries<\/code> method. Each even-indexed element becomes a key, and the corresponding odd-indexed element becomes the value.<\/p>\nUse an array of objects:<\/li>\n<\/p>\n
const array = [{ key: \"key1\", value: \"value1\" }, { key: \"key2\", value: \"value2\" }];
\nconst obj = Object.assign({}, ...array.map(item => ({ [item.key]: item.value })));
\nconsole.log(obj[\"key2\"]); \/\/ Output: value2<\/code><\/pre>\n<\/p>\n
In this approach, we use an array of objects instead of a regular array. We then convert the array of objects into a single object using the Object.assign<\/code> method, making key-value pairs accessible.<\/p>\nCreate a utility function:<\/li>\n<\/p>\n
function getKeyByKey(arr, key) {
\n for (let i = 0; i < arr.length; i++) {
\n if (arr[i] === key) {
\n return arr[i + 1];
\n }
\n }
\n return undefined;
\n}
\n
\nconst array = [\"key1\", \"value1\", \"key2\", \"value2\"];
\nconsole.log(getKeyByKey(array, \"key2\")); \/\/ Output: value2<\/code><\/pre>\n<\/p>\n
This approach involves creating a utility function that iterates through the array, finding the element with the specified key and returning the next element as its value.<\/p>\n
\n<\/ol>\n