<\/span><\/h3>\nBy iterating over each element in the array, we can compare them to find the lowest value.<\/p>\n
“`javascript
\nlet array = [5, 10, 3, 8, 2];
\nlet lowest = array[0];<\/p>\n
for(let i = 1; i < array.length; i++) {
\n if(array[i] < lowest) {
\n lowest = array[i];
\n }
\n}<\/p>\n
console.log(“The lowest value is: ” + lowest);
\n“`<\/p>\n
Method 2: Using Math.min() and the spread operator<\/strong><\/p>\nThe spread operator (…) can be used to pass the array elements as arguments to Math.min() function, returning the lowest value.<\/p>\n
“`javascript
\nlet array = [5, 10, 3, 8, 2];
\nlet lowest = Math.min(…array);<\/p>\n
console.log(“The lowest value is: ” + lowest);
\n“`<\/p>\n
Method 3: Using Array.reduce()<\/strong><\/p>\nThe Array.reduce() method can be utilized to sequentially reduce the array to a single value, in this case finding the lowest value.<\/p>\n
“`javascript
\nlet array = [5, 10, 3, 8, 2];
\nlet lowest = array.reduce((acc, current) => Math.min(acc, current));<\/p>\n
console.log(“The lowest value is: ” + lowest);
\n“`<\/p>\n
Method 4: Using the spread operator and Math.min.apply()<\/strong><\/p>\nSometimes, when dealing with older browsers that don’t support the spread operator, you can use the apply() method to execute Math.min() on the array elements.<\/p>\n
“`javascript
\nlet array = [5, 10, 3, 8, 2];
\nlet lowest = Math.min.apply(null, array);<\/p>\n
console.log(“The lowest value is: ” + lowest);
\n“`<\/p>\n