<\/span><\/h2>\nOne straightforward approach to finding the smallest value in an array is by using a linear search method. This method involves iterating over each element in the array and comparing it with the current minimum value. Let’s take a look at the code snippet below to see how this can be achieved:<\/p>\n
“`cpp
\n#include <\/p>\nint findSmallestValue(int arr[], int size) {
\n int minValue = arr[0];
\n for (int i = 1; i < size; i++) {
\n if (arr[i] < minValue) {
\n minValue = arr[i];
\n }
\n }
\n return minValue;
\n}<\/p>\n
int main() {
\n int array[] = {5, 11, 2, 8, 15, 1};
\n int size = sizeof(array) \/ sizeof(array[0]);<\/p>\n
int smallestValue = findSmallestValue(array, size);
\n std::cout << \"The smallest value in the array is: \" << smallestValue << std::endl;\n\n\n return 0;
\n}
\n“`<\/p>\n
The code above demonstrates a simple function, `findSmallestValue`, that takes an integer array and its size as input. It initializes `minValue` with the first element of the array and then compares it with each subsequent element. If a smaller value is found, `minValue` is updated accordingly. Finally, the function returns `minValue`.<\/p>\n
Using this approach, the smallest value in the given array `5, 11, 2, 8, 15, 1` is determined to be **1**.<\/p>\n